FFR, quick help, plz? Math/test tomorrow/lost

**Shadowcliff** · 11-9-2010, 09:40 PM

I have an algebra (II) test tomorrow.
I'm at a loss.
Comepletely drew a blank on addition/subtraction problems.
I know that if I figure out just one it won't be a problem.

Here's an example:

(4/3z)+(2/z)=(5/6)

Found the LCD, 6z. Then what?

Thanks.

Relambrien · 11-9-2010, 09:47 PM

For future reference, you can go to this subforum if you want academic or homework help: http://www.flashflashrevolution.com/...splay.php?f=68

**Patashu** · 11-9-2010, 09:48 PM

Here's how I'd solve it:
(4/3z)+(2/z)=(5/6)
Multiply all terms by z.
4/3 + 2 = (5/6)*z
Divide both sides by 5/6.
(6/5)*(4/3+2) = z

who_cares973 · 11-9-2010, 09:51 PM

patashu isnt a math major he doesnt know what he's doing dont listen to him

**rushyrulz** · 11-9-2010, 09:53 PM

common denominator is 3x after multiplying (2/x) by (3/3)
You should then have (4/3x)+(6/3x)=5/6 which is equal to (10/3x)=5/6
Then multiply both sides by 3x to get it out of the denominator and you should get 10=(15x/6).
Multiply both sides by 6 to get 60=15x

I think you can solve it from here.

Oh, and I switched the zs with xs because variable z confuses me and should never be a variable >.<

**Jtehanonymous** · 11-9-2010, 09:54 PM

Did you try integrating? :/

This is how I'd try it:
(4/3z)+(2/z)=(5/6)

Multiply everything by 6z.

8 + 12 = 5z

20 = 5z

4 = z

**Shadowcliff** · 11-9-2010, 09:58 PM

Thanks Relambrien, and jtehanonymous, that's just was I was looking for. I get it now.

Haha. I swear I'm not stupid. We're way ahead of this, but it's showing up in a test tomorrow and somehow it got flushed out of my brain.

**rushyrulz** · 11-9-2010, 10:09 PM

Quote:

Originally Posted by Shadowcliff

Thanks Relambrien, and jtehanonymous, that's just was I was looking for. I get it now.

You're welcome >.<

**Shadowcliff** · 11-9-2010, 10:14 PM

Quote:

Originally Posted by rushyrulz

You're welcome >.<

Sorry, his was a little simpler D:
It was more like what my teacher would expect.

11-9-2010, 09:40 PM	#1
Shadowcliff FFR Veteran Join Date: Jan 2008 Location: Cary, NC Age: 29 Posts: 695	FFR, quick help, plz? Math/test tomorrow/lost I have an algebra (II) test tomorrow. I'm at a loss. Comepletely drew a blank on addition/subtraction problems. I know that if I figure out just one it won't be a problem. Here's an example: (4/3z)+(2/z)=(5/6) Found the LCD, 6z. Then what? Thanks.

11-9-2010, 09:47 PM	#2
Relambrien FFR Player Join Date: Dec 2006 Location: Pittsburgh, PA Age: 32 Posts: 1,644	Re: FFR, quick help, plz? Math/test tomorrow/lost For future reference, you can go to this subforum if you want academic or homework help: http://www.flashflashrevolution.com/...splay.php?f=68

11-9-2010, 09:48 PM	#3
Patashu FFR Simfile Author Join Date: Apr 2006 Location: we traced the call...it's coming from inside the house Age: 33 Posts: 8,609	Re: FFR, quick help, plz? Math/test tomorrow/lost Here's how I'd solve it: (4/3z)+(2/z)=(5/6) Multiply all terms by z. 4/3 + 2 = (5/6)z Divide both sides by 5/6. (6/5)(4/3+2) = z __________________ Patashu makes Chiptunes in Famitracker: http://soundcloud.com/patashu/8bit-progressive-metal-fading-world http://img.photobucket.com/albums/v216/Mechadragon/smallpackbanner.png Best non-AAAs: ERx8 v2 (14-1-0-4), Hajnal (3-0-0-0), RunnyMorning (8-0-0-4), Xeno-Flow (1-0-0-3), Blue Rose (35-2-0-20), Ketsarku (14-0-0-0), Silence (1-0-0-0), Lolo (14-1-0-1) http://i231.photobucket.com/albums/ee301/xiaoven/solorulzsig.png

11-9-2010, 09:51 PM	#4
who_cares973 FFR Player Join Date: Aug 2006 Location: :U Age: 35 Posts: 15,407	Re: FFR, quick help, plz? Math/test tomorrow/lost patashu isnt a math major he doesnt know what he's doing dont listen to him __________________

11-9-2010, 09:53 PM	#5
rushyrulz Digital Dancing! Join Date: Feb 2006 Location: 80 billion club, NE Age: 31 Posts: 12,981	Re: FFR, quick help, plz? Math/test tomorrow/lost common denominator is 3x after multiplying (2/x) by (3/3) You should then have (4/3x)+(6/3x)=5/6 which is equal to (10/3x)=5/6 Then multiply both sides by 3x to get it out of the denominator and you should get 10=(15x/6). Multiply both sides by 6 to get 60=15x I think you can solve it from here. Oh, and I switched the zs with xs because variable z confuses me and should never be a variable >.< __________________ Last edited by rushyrulz; 11-9-2010 at 09:58 PM..

11-9-2010, 09:58 PM	#7
Shadowcliff FFR Veteran Join Date: Jan 2008 Location: Cary, NC Age: 29 Posts: 695	Re: FFR, quick help, plz? Math/test tomorrow/lost Thanks Relambrien, and jtehanonymous, that's just was I was looking for. I get it now. Haha. I swear I'm not stupid. We're way ahead of this, but it's showing up in a test tomorrow and somehow it got flushed out of my brain.

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