Random credit giveaway.

**nuclearsamurai** · 12-15-2008, 07:40 PM

Ready, and...the giveaway is over.

If you're reading this, you're too late.

**xealix** · 12-15-2008, 07:46 PM

uhm what? i just came here for some free credits hahahah.

**nuclearsamurai** · 12-15-2008, 07:47 PM

I did say this would take some work.

xD

EDIT: Brb, playing FFR for a while so whoever answers correctly gets a little more credits.

EDIT II: +11 credits.

**xealix** · 12-15-2008, 07:50 PM

well i dont know if this is right but i looked it up xp

c = i gives the sequence 0, i, (−1 + i), −i, (−1 + i), −i…, which is bounded, and so it belongs to the Mandelbrot set.

dont really know what that means though hahaha

BTW i am going to be studying this all night now in an attempt to further my limited knowledge
chances are it will end in catastrophe (or i will just give up)

**nuclearsamurai** · 12-15-2008, 08:07 PM

Quote:

Originally Posted by xealix

BTW i am going to be studying this all night now in an attempt to further my limited knowledge
chances are it will end in catastrophe (or i will just give up)

I can gather from this statement that you didn't work on it at all.

**xealix** · 12-15-2008, 08:14 PM

I did. . .for like 10 minutes. Hey what can i say i get bored easily and i don't have a math teacher to help me. Sometime i really miss my math teachers Xp

**nuclearsamurai** · 12-15-2008, 08:15 PM

Justify your answer with absolute value and you can have them.

That's all.

**xealix** · 12-15-2008, 08:17 PM

Ill just have to push myself. . .

Edit: note to self: so far im the only one in this

**Bolth mannn** · 12-15-2008, 08:17 PM

i came up with 3 anwers...

42, 69, pi...

**nuclearsamurai** · 12-15-2008, 08:19 PM

Quote:

Originally Posted by Bolth mannn

42

Wrong.

Quote:

Originally Posted by Bolth mannn

69

Wrong.

Quote:

Originally Posted by Bolth mannn

pi...

Wrong.

Keep trying.

EDIT: Xealix, not anymore.

**xealix** · 12-15-2008, 08:31 PM

maybe this will help. . .

That is, a complex number, c, is in the Mandelbrot set if, when starting with z0=0 and applying the iteration repeatedly, the absolute value of zn never exceeds a certain number (that number depends on c) however large n gets.

cause i wont get this. . .
maybe 0?? or what ever # applies
hmmm. . .

**nuclearsamurai** · 12-15-2008, 08:36 PM

Ah, close enough.

Here you go.

**xealix** · 12-15-2008, 08:39 PM

wicked awesome hahaha

**sumzup** · 12-15-2008, 08:41 PM

A mandelbrot set requires that |c| <2 (if |z|>2, then |z^2 +c | ≥ |z^2|-|c| > 2|z|-|c|. If |z|>|c|, then 2|z| - |c| > |z|. so, if |z| > 2 and |z| > |c|, then |z^2 + c| > |z|, so the sequence is increasing, and eventually goes to infinity for |c| >2). |i| = 1, which is less than 2. Thus, c = i is contained within the mandelbrot set.

Ice wolf · 12-15-2008, 08:48 PM

Wrecked?

**nuclearsamurai** · 12-15-2008, 08:51 PM

Quote:

Originally Posted by sumzup

A mandelbrot set requires that |c| <2 (if |z|>2, then |z^2 +c | ≥ |z^2|-|c| > 2|z|-|c|. If |z|>|c|, then 2|z| - |c| > |z|. so, if |z| > 2 and |z| > |c|, then |z^2 + c| > |z|, so the sequence is increasing, and eventually goes to infinitiy for |c| >2). |i| = 1, which is less than 2. Thus, c = i is contained within the mandelbrot set.

See, this is the answer I was looking for. Here you go.

**xealix** · 12-15-2008, 09:00 PM

i have been bested.

**sumzup** · 12-15-2008, 09:01 PM

Awesome! Thanks so much. I won't deny that I used Google, but I integrated my findings along with some random personal insight to come up with something that made sense to me (and apparently to you as well).

Edit: xealix: eh, you were pretty close; you just needed to express it properly

**nuclearsamurai** · 12-15-2008, 09:05 PM

Quote:

Originally Posted by sumzup

Edit: xealix: eh, you were pretty close; you just needed to express it properly

This.

And the giveaway's over.

**xealix** · 12-15-2008, 09:09 PM

Quote:

Originally Posted by sumzup

Awesome! Thanks so much. I won't deny that I used Google, but I integrated my findings along with some random personal insight to come up with something that made sense to me (and apparently to you as well).

Edit: xealix: eh, you were pretty close; you just needed to express it properly

Quote:

Originally Posted by nuclearsamurai

This.

And the giveaway's over.

ahh. . . well i came out of this smarter and that's what really matters. im still quite aways from getting back to 40k credits though xp

12-15-2008, 07:40 PM	#1
nuclearsamurai huehuehue Join Date: Jul 2007 Location: Ithaca, NY Age: 32 Posts: 1,211	Random credit giveaway. Ready, and...the giveaway is over. If you're reading this, you're too late. __________________ Last edited by nuclearsamurai; 12-15-2008 at 09:06 PM..

12-15-2008, 07:46 PM	#2
xealix One Among The Fence Join Date: Feb 2007 Location: iowa Age: 33 Posts: 680	Re: Random credit giveaway. uhm what? i just came here for some free credits hahahah.

12-15-2008, 07:47 PM	#3
nuclearsamurai huehuehue Join Date: Jul 2007 Location: Ithaca, NY Age: 32 Posts: 1,211	Re: Random credit giveaway. I did say this would take some work. xD EDIT: Brb, playing FFR for a while so whoever answers correctly gets a little more credits. EDIT II: +11 credits. __________________ Last edited by nuclearsamurai; 12-15-2008 at 07:52 PM..

12-15-2008, 07:50 PM	#4
xealix One Among The Fence Join Date: Feb 2007 Location: iowa Age: 33 Posts: 680	Re: Random credit giveaway. well i dont know if this is right but i looked it up xp c = i gives the sequence 0, i, (−1 + i), −i, (−1 + i), −i…, which is bounded, and so it belongs to the Mandelbrot set. dont really know what that means though hahaha BTW i am going to be studying this all night now in an attempt to further my limited knowledge chances are it will end in catastrophe (or i will just give up) Last edited by xealix; 12-15-2008 at 07:54 PM.. Reason: to add slight amounts of joy to the world (ragle fragle)

12-15-2008, 08:14 PM	#6
xealix One Among The Fence Join Date: Feb 2007 Location: iowa Age: 33 Posts: 680	Re: Random credit giveaway. I did. . .for like 10 minutes. Hey what can i say i get bored easily and i don't have a math teacher to help me. Sometime i really miss my math teachers Xp

12-15-2008, 08:15 PM	#7
nuclearsamurai huehuehue Join Date: Jul 2007 Location: Ithaca, NY Age: 32 Posts: 1,211	Re: Random credit giveaway. Justify your answer with absolute value and you can have them. That's all. __________________

12-15-2008, 08:17 PM	#8
xealix One Among The Fence Join Date: Feb 2007 Location: iowa Age: 33 Posts: 680	Re: Random credit giveaway. Ill just have to push myself. . . Edit: note to self: so far im the only one in this Last edited by xealix; 12-15-2008 at 08:18 PM.. Reason: gosh darn my forgetfulness

12-15-2008, 08:17 PM	#9
Bolth mannn FFR Veteran Join Date: Aug 2008 Age: 29 Posts: 2,228	Re: Random credit giveaway. i came up with 3 anwers... 42, 69, pi... __________________

12-15-2008, 08:31 PM	#11
xealix One Among The Fence Join Date: Feb 2007 Location: iowa Age: 33 Posts: 680	Re: Random credit giveaway. maybe this will help. . . That is, a complex number, c, is in the Mandelbrot set if, when starting with z0=0 and applying the iteration repeatedly, the absolute value of zn never exceeds a certain number (that number depends on c) however large n gets. cause i wont get this. . . maybe 0?? or what ever # applies hmmm. . .

12-15-2008, 08:36 PM	#12
nuclearsamurai huehuehue Join Date: Jul 2007 Location: Ithaca, NY Age: 32 Posts: 1,211	Re: Random credit giveaway. Ah, close enough. Here you go. __________________

12-15-2008, 08:39 PM	#13
xealix One Among The Fence Join Date: Feb 2007 Location: iowa Age: 33 Posts: 680	Re: Random credit giveaway. wicked awesome hahaha

12-15-2008, 08:41 PM	#14
sumzup (+ (- (/ (* 1 2) 3) 4) 5) Join Date: Nov 2005 Location: Seattle Age: 33 Posts: 1,398	Re: Random credit giveaway. A mandelbrot set requires that \|c\| <2 (if \|z\|>2, then \|z^2 +c \| ≥ \|z^2\|-\|c\| > 2\|z\|-\|c\|. If \|z\|>\|c\|, then 2\|z\| - \|c\| > \|z\|. so, if \|z\| > 2 and \|z\| > \|c\|, then \|z^2 + c\| > \|z\|, so the sequence is increasing, and eventually goes to infinity for \|c\| >2). \|i\| = 1, which is less than 2. Thus, c = i is contained within the mandelbrot set. __________________ Last edited by sumzup; 12-15-2008 at 08:57 PM.. Reason: spelled infinity wrong

12-15-2008, 08:48 PM	#15
Ice wolf FFR Player Join Date: Feb 2007 Location: The 10th Dimension Posts: 852	Re: Random credit giveaway. Wrecked? __________________ Reverse for life! ^Way better than 25thhour's link. You know you want to sign up. The best noteskin ever: Skittles Are you having trouble syncing your files? Use DDReamStudio.

12-15-2008, 09:00 PM	#17
xealix One Among The Fence Join Date: Feb 2007 Location: iowa Age: 33 Posts: 680	Re: Random credit giveaway. i have been bested.

12-15-2008, 09:01 PM	#18
sumzup (+ (- (/ (* 1 2) 3) 4) 5) Join Date: Nov 2005 Location: Seattle Age: 33 Posts: 1,398	Re: Random credit giveaway. Awesome! Thanks so much. I won't deny that I used Google, but I integrated my findings along with some random personal insight to come up with something that made sense to me (and apparently to you as well). Edit: xealix: eh, you were pretty close; you just needed to express it properly __________________

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